So say I start with 1000 dollars. Bet 5 dollars a hand. When I lose, I double the bet, meaning that the loss is recouped. If you lose twice, double it again, betting 20. Keep doubling until you win, and you are back to even plus your original bet. Foolproof? Because the chances of losing 6 or 7 hands in a row is so slim, there is little to no chance of losing. Tell me what you think.
If the dealer has ace on he ‘s hand, and i took insurance. then if the dealer really got blackjack/21, do i get pay to my insurance and the original $? or just the insurance.
I can count cards and I was wondering where on the internet I can find a chart that accurately deviates (changes) from Basic Strategy based upon the count. If you know where to find one, please give a link or tell me the website name.
In blackjack, if I KNOW that the deck is heavy (more tens and aces) than in a full deck (as compared to small cards), should I increase my bet, maximizing possibility of blackjack? Or should I be increasing bet when the deck is light, on theory that dealer will probably have to work harder?
if i play any card game, say blackjack… starting with $100 and betting $10 each hand, how much should i be able to have won in order for me to leave the casino before it takes down my winnings? (PS: Please don’t post any “gamble is bad don’t do it” i’m old enough to know what’s good for me thanks)
Everytime you loose you double the bet on the next hand until you win again. At the point you win, you have won back all your loses. You would need a big bank roll. If you bet $10 a hand, the next would cost $20, then $40, $80, $160, $320. Once you win you switch back to your regular betting of $10.
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